(-81)z^2-72z+6=(-81)((z+4/9)^2-22/81)

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Solution for (-81)z^2-72z+6=(-81)((z+4/9)^2-22/81) equation: 


z in (-oo:+oo)

6-81*z^2-(72*z) = -81*((z+4/9)^2-(22/81)) // + -81*((z+4/9)^2-(22/81))

6-(-81*((z+4/9)^2-(22/81)))-81*z^2-(72*z) = 0

81*((z+4/9)^2-22/81)-81*z^2-72*z+6 = 0

81*((z+4/9)^2-22/81)-81*z^2-72*z+6 = 0

72*z-72*z-6+6 = 0

6-6 = 0

0 = 0

0 = 0

z belongs to the empty set

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